C Program to Display same Source Code as Output

#include<stdio.h>

int main(){
    FILE *fp;
    char c;

    fp = fopen(__FILE__,"r");

    do{
         c= getc(fp);
         putchar(c);
    }
    while(c!=EOF);

    fclose(fp);

    return 0;
}
Output :

#include<stdio.h>

int main(){
    FILE *fp;
    char c;

    fp = fopen(__FILE__,"r");

    do{
         c= getc(fp);
         putchar(c);
    }
    while(c!=EOF);

    fclose(fp);

    return 0;
}

C Program to Multiply two Matrices using Recursion

#include<stdio.h>
#define MAX 10

void matMult(int [MAX][MAX],int [MAX][MAX]);
int r1,r2,c1,c2;
int c[MAX][MAX];

int main(){

    int a[MAX][MAX],b[MAX][MAX],i,j,k;

    printf("Enter the row and column of first matrix: ");
    scanf("%d%d",&r1,&c1);
    printf("Enter the row and column of second matrix: ");
    scanf("%d%d",&r2,&c2);

    if(c1!=o){
         printf("Matrix mutiplication is not possible");
    }
  else{

      printf("Enter the First matrix: ");
      for(i=0;i<r1;i++)
      for(j=0;j<c1;j++)
           scanf("%d",&a[i][j]);

      printf("Enter the Second matrix: ");
      for(i=0;i<r2;i++)
      for(j=0;j<c2;j++)
           scanf("%d",&b[i][j]);

      printf("nThe First matrix is: n");
      for(i=0;i<r1;i++){
      printf("n");
      for(j=0;j<c1;j++){
           printf("%dt",a[i][j]);
      }
      }

      printf("nThe Second matrix is: n");
      for(i=0;i<r2;i++){
      printf("n");
      for(j=0;j<c2;j++){
           printf("%dt",b[i][j]);
      }
      }

      matMult(a,b);

  }

  printf("nThe multiplication of two matrixes is: n");
  for(i=0;i<r1;i++){
      printf("n");
      for(j=0;j<c2;j++){
           printf("%dt",c[i][j]);
      }
  }
  return 0;
}

void matMult(int a[MAX][MAX],int b[MAX][MAX]){

    static int sum,i=0,j=0,k=0;

    if(i<r1) //row of first matrix
    {
      if(j<c2) //column of second matrix
      {
         if(k<c1)
         {
             sum=sum+a[i][k]*b[k][j];
             k++;
             matMult(a,b);
         }
         c[i][j]=sum;
             sum=0;
             k=0;
             j++;
             matMult(a,b);
      }
        j=0;
        i++;
        matMult(a,b);
    }
}
output :

Enter the row and column of first matrix: 2 2
Enter the row and column of second matrix: 2 2
Enter the First matrix: 1 2 3 4
Enter the Second matrix: 1 2 1 2

The First matrix is:

1       2
3       4
The Second matrix is:

1       2
1       2
The multiplication of two matrixes is:

3       6
7       14

C Program to implement Binary Search Tree Traversal

# include <stdio.h>
# include <conio.h>
# include <stdlib.h>

typedef struct BST
{
    int data;
    struct BST *lchild,*rchild;
}node;

void insert(node *,node *);
void inorder(node *);
void preorder(node *);
void postorder(node *);
node *search(node *,int,node **);

void main()
{
 int choice;
 char ans='N';
 int key;
 node *new_node,*root,*tmp,*parent;
 node *get_node();
 root=NULL;
 clrscr();

 printf("nProgram For Binary Search Tree ");
 do
 {
   printf("n1.Create");
   printf("n2.Search");
   printf("n3.Recursive Traversals");
   printf("n4.Exit");
   printf("nEnter your choice :");
   scanf("%d",&choice);

   switch(choice)
   {
    case 1:
           do
             {
             new_node=get_node();

             printf("nEnter The Element ");
             scanf("%d",&new_node->data);

             if(root==NULL)   /* Tree is not Created */
                 root=new_node;
             else
                 insert(root,new_node);

             printf("nWant To enter More Elements?(y/n)");
             ans=getch();

             }while(ans=='y');

             break;

     case 2:
             printf("nEnter Element to be searched :");
             scanf("%d",&key);

             tmp = search(root,key,&parent);

             printf("nParent of node %d is %d",
                              tmp->data,parent->data);
             break;

    case 3:

            if(root==NULL)
                printf("Tree Is Not Created");
            else
               {
               printf("nThe Inorder display : ");
               inorder(root);
               printf("nThe Preorder display : ");
               preorder(root);
               printf("nThe Postorder display : ");
               postorder(root);
               }

            break;
    }
 }while(choice!=4);
}
/*
  Get new Node
*/
node *get_node()
 {
 node *temp;
 temp=(node *)malloc(sizeof(node));
 temp->lchild=NULL;
 temp->rchild=NULL;
 return temp;
 }
/*
  This function is for creating a binary search tree
*/
void insert(node *root,node *new_node)
{
  if(new_node->data < root->data)
     {
     if(root->lchild==NULL)
         root->lchild = new_node;
     else
         insert(root->lchild,new_node);
     }

  if(new_node->data > root->data)
     {
     if(root->rchild==NULL)
         root->rchild=new_node;
     else
         insert(root->rchild,new_node);
     }
}
/*
This function is for searching the node from
      binary Search Tree
*/
node *search(node *root,int key,node **parent)
{
 node *temp;
 temp=root;
    while(temp!=NULL)
    {
      if(temp->data==key)
         {
         printf("n The %d Element is Present",temp->data);
         return temp;
         }
      *parent=temp;

      if(temp->data>key)
         temp=temp->lchild;
      else
         temp=temp->rchild;
    }
 return NULL;
}
/*
This function displays the tree in inorder fashion
*/
void inorder(node *temp)
{
   if(temp!=NULL)
    {
    inorder(temp->lchild);
    printf("%d",temp->data);
    inorder(temp->rchild);
    }
}
/*
This function displays the tree in preorder fashion
*/
void preorder(node *temp)
{
 if(temp!=NULL)
    {
    printf("%d",temp->data);
    preorder(temp->lchild);
    preorder(temp->rchild);
    }
}

/*
This function displays the tree in postorder fashion
*/
void postorder(node *temp)
{
 if(temp!=NULL)
    {
    postorder(temp->lchild);
    postorder(temp->rchild);
    printf("%d",temp->data);
    }
}
[468x15]
Output :
Program For Binary Search Tree
1.Create
2.Search
3.Recursive Traversals
4.Exit
Enter your choice :1

Enter The Element 5

Do u Want To enter More Elements?(y/n)
Enter The Element 12

Do u Want To enter More Elements?(y/n)
Enter The Element 6

Do u Want To enter More Elements?(y/n)
Enter The Element 3

Do u Want To enter More Elements?(y/n)
1.Create
2.Search
3.Recursive Traversals
4.Exit
Enter your choice :3

The Inorder   display  :   3  5  6  12
The Preorder  display  :   5  3  12  6
The Postorder display  :   3  6  12  5

1.Create
2.Search
3.Recursive Traversals
4.Exit
Enter your choice :2

Enter Element to be searched :3

The 20 Element is Present
Parent of node 3 is 5

C program using pointers to read in an array of integers and print its elements in reverse order.

#include<stdio.h>
#include<conio.h>
#define MAX 30

void main()
{
int size,i,arr[MAX];
int *ptr;
clrscr();

ptr=&arr[0];

printf("Enter the size of array : ");
scanf("%d",&size);

printf("nEnter %d integers into array:n",size);
   for(i=0;i<size;i++)
   {
   scanf("%d",ptr);
   ptr++;
   }

ptr=&arr[size-1];

printf("nElements of array in reverse order are:n");

 for(i=size-1;i>=0;i--)
   {
   printf("nElement%d is %d :",i,*ptr);
   ptr--;
   }

getch();
}
Output :

Enter the size of array : 5
Enter 5 integers into array : 11 22 33 44 55
Elements of array in reverse order are :
Element 4 is : 55
Element 4 is : 44
Element 4 is : 33
Element 4 is : 22
Element 4 is : 11

C Program to Implement Stack Operations Using Array

#include<stdio.h>
#define M 50
struct state
{
    char name[50];
    long int population;
    float literacyRate;
    float income;
}st[M];     /* array of structure */
int main()
{
int i,n,ml,mi,maximumLiteracyRate, maximumIncome;
float rate;
ml = mi =-1;
maximumLiteracyRate = maximumIncome = 0;

printf("Enter how many states:");
scanf("%d",&n);
for(i=0;i<n;i++)
  {
    printf("\nEnter state %d details :",i);
    printf("\n\nEnter state name : ");
    scanf("%s",&st[i].name);
    printf("\nEnter total population : ");
    scanf("%ld",&st[i].population);
    printf("\nEnter total literary rate : ");
    scanf("%f",&rate);
    st[i].literacyRate = rate;
    printf("\nEnter total income : ");
    scanf("%f",&st[i].income);
  }
for(i=0;i<n;i++)
{
    if(st[i].literacyRate >= maximumLiteracyRate)
        {
        maximumLiteracyRate = st[i].literacyRate;
        ml++;
        }
    if(st[i].income > maximumIncome)
        {
        maximumIncome = st[i].income;
        mi++;
        }
}
printf("\nState with highest literary rate :%s",st[ml].name);
printf("\nState with highest income :%s",st[mi].name);
return(0);
}
Output :
Enter how many states:3

Enter state 0 details :

Enter state name : Maharashtra

Enter total population : 1000

Enter total literary rate : 90

Enter total income : 10000

Enter state 1 details :

Enter state name : Goa

Enter total population : 300

Enter total literary rate : 94

Enter total income : 5000

Enter state 2 details :

Enter state name : Gujrat

Enter total population : 900

Enter total literary rate : 78

Enter total income : 7000

The state whose literary rate is the highest : Goa
The state whose income is the highest : Maharashtra

C Program to implement 4-Queens Problem using Backtracking

#include<stdio.h>

#include<conio.h>

#include<math.h>

char a[10][10];

int n;

void printmatrix()

{

 int i,j;

 printf("n");

 for(i=0;i < n;i++)

       {

       for(j=0;j < n;j++)

            printf("%ct",a[i][j]);

       printf("nn");

       }

}

int getmarkedcol(int row)

{

       int i,j;

       for(i=0;i < n;i++)

       if(a[row][i]=='Q')

       {

                       return(i);

                       break;

       }

}

int feasible(int row, int col)

{

 int i,tcol;

 for(i=0;i < n;i++)

       {

     tcol=getmarkedcol(i);

           if(col==tcol || abs(row-i)==abs(col-tcol))

              return 0;

       }

       return 1;

}

void nqueen(int row)

{

 int i,j;

 if(row < n)

 {

                for(i=0;i < n;i++)

 {

                                       if(feasible(row,i))

      {

                                                       a[row][i]='Q';

                                                        nqueen(row+1);

                                                       a[row][i]='.';

                                       }

                       }

       }

       else

       {

                       printf("nThe solution is:- ");

                       printmatrix();

       }

}

void main()

{

       int i,j;

       clrscr();

printf("n Enter the no. of queens:- ");

       scanf("%d",&n);

       for(i=0;i < n;i++)

                       for(j=0;j < n;j++)

                                       a[i][j]='.';

       nqueen(0);

       getch();

}

Armstrong Number Using C++

/*Armstrong Number  Using C++ Program  CHECK THE GIVEN NUMBER IS ARMSTRONG OR NOT

FOR EXAMPLE
153/1^3+5^3+3^3=153
*/
#include<iostream.h>
#include<conio.h>
void main()
{
  clrscr();
  int i,n,m,re,sum=0;
  cout<<"enter the required number";
  cin>>n;
  m=n;
  while(m>0)
   {
    re=m%10;
    m=m/10;
    sum=sum+re*re*re;
   }
  if(sum==n)
   {
    cout<<"given number"<<n<<"is armstrong";
   }
  else
   {
    cout<<"given number"<<<n<"is not armstrong";
   }
  getch();
}