Sunday, 6 July 2014

Linear linked list structure In C Programming

#include<stdio.h>
#include<conio.h>

/*contains malloc & free functions */
#define NULL 0
struct node{
int info;
struct node *next;
};
typedef struct node nodeptr;
int menu(void);
void insertEnd(nodeptr **, int);/*insert to the end of the list*/
void deleteEnd(nodeptr **, int *);/*delete from the end " " "*/
void displayList(nodeptr *);
nodeptr *getnode(void);
void freenode(nodeptr *);
int main()
{
int choice,x;
nodeptr *List= NULL; /*List points the beginning of the list*/
do{
choice = menu();
switch(choice){
case 1:
printf("Enter new data item:");
scanf("%d",&x);
insertEnd(&List,x);
break;
case 2:
deleteEnd(&List,&x);
printf("The deleted data item is: %d",x);
break;
case 3:
displayList(List);
break;
default:
if(choice == 4)
printf("\nEnd of the Program");
else
printf("\nEnter the choice again");
break;
}
}while(choice !=4);
return 0;
}

/*
Use double pointer if you are changing the
content of the List which is a pointer to the
beginning of the Linked List.
Use single pointer if you are not changing the
content of the List which is a pointer to the
beginning of the Linked List.*/

int menu(void)
{
int c;
printf("\nMain Menu:\n");
printf("1 - Insert an item\n");
printf("2 - Delete an item\n");
printf("3 - Display the Linked List items\n");
printf("4 - Quit\n\n");
scanf("%d",&c);
return c;
}
void insertEnd(nodeptr **plist, int x)
{
nodeptr *p, *q;
p=getnode();
p->info = x;
p->next = NULL;
if(*plist == NULL)
*plist = p;
else{
q = *plist;
while(q->next != NULL)
q = q->next;
q->next = p;
}
}
void deleteEnd(nodeptr **plist, int *px)
{
nodeptr *p,*q;
if(*plist == NULL){
printf("void deletion\n");
return;
}
p = *plist; /*current node*/
q = p->next; /*the node after the current node*/
if(q == NULL){
*px = p->info; /*the data of the deleted element*/
freenode(p);
*plist = NULL;
}
else{
while(q->next != NULL){
p = p->next; /*go to the next node*/
q = p->next;
}
p->next = NULL;
*px = q->info; /*the data of the deleted element*/
freenode(q);
}
}

/*
Use double pointer if you are changing the
content of the plist which is a pointer to the
beginning of the Linked List.
Use double pointer if you are changing the
content of the plist which is a pointer to the
beginning of the Linked List.
*/

void displayList(nodeptr *plist)
{
nodeptr *p;
p = plist; /*current node*/
if(p == NULL){
printf("no node/data is available in the list\n");
return;
}
while(p!= NULL){
printf("%5d", p->info); /*prints the current data*/
p = p->next;
}
}
nodeptr *getnode(void)
{
nodeptr *p;
p = (nodeptr *) malloc(sizeof(nodeptr));
return p;
}
void freenode(nodeptr *p)
{
free(p);
}

Wednesday, 11 June 2014

stack implementation using Linked List In C Programing

#include<stdio.h>
#include<conio.h>
void push_stack ();
void pop_stack ();
void display_stack ();

typedef struct node
{
int data_stack ;
struct node *link;
}d;
d*top=NULL;


main()
{
int d;
printf("\tMENU\n1.PUSH_STACK \n2.POP_STACK \n3.DISPLAY_STACK \n4.EXIT\n");
do
{
printf("\nEnter your choice\n");
scanf("%d",&d);
switch(d)
{
case 1:
push_stack ();
break;
case 2:
pop_stack ();
break;
case 3:
display_stack ();
break;
case 4:
break;
default:
printf("Invalid choice\n");
break;
}
}
while(d!=4);
}


void push_stack ()
{
int item;
d *temp;
printf("Enter the item\n");
scanf("%d",&item);
temp=(d*)malloc(sizeof(d));
temp->data_stack =item;
temp->link=top;
top=temp;
}

void pop_stack ()
{
d *temp;
if(top==NULL)
printf("Stack is empty\n");
else
{
temp=top;
printf("The element deleted = %d\n",temp->data_stack );
top=top->link;

free(temp);
}
}

void display_stack ()
{
d *save;
if(top==NULL)
printf("Stack is empty\n");
else
{
save=top;
printf("The elements of the stack are :");
while(save!=NULL)
{
printf("%d\t",save->data_stack );
save=save->link;
}
printf("\nTopmost element = %d\n",top->data_stack );
}
}

Create Stack And Insert Data Using C Programming

#include<stdio.h>
#include<conio.h>
#define col 4
#define row 4

void main()
{
            int i,n,j;
            float ax[row+1], ay[col+1],diff[row+1][col+1],x,p,ya1,ya2,ya3,ya4,ya,ha;

            clrscr();

            printf("Enter thae value of n:");
            scanf("%d",&n);

            printf("\n Enter thae values of X and Y:\n");
            for(i=0; i<=n; i++)
            {
                        scanf("%f %f",&ax[i],&ay[i]);
            }

            printf("Value of X:");
            scanf("%f",&x);

            ha=ax[1]-ax[0];

            for(i=0; i<=n-1; i++)
                        diff[i][1]=ay[i+1]-ay[i];
            for(j=2; j<=row; j++)
                        for(i=0; i<=n-j; i++)
                                    diff[i][j]=diff[i+1][j-1]-diff[i][j-1];

            p=(x-ax[0])/ha;
            ya1=p*diff[0][1];
            ya2=p*(p-1)*diff[0][2]/2;
            ya3=p*(p-1)*(p-2)*diff[0][3]/6;
            ya4=p*(p-1)*(p-2)*(p-3)*diff[0][4]/24;
            ya=ay[0]+ya1+ya2+ya3+ya4;
            printf("%f",ya);
            getcha();



}

Create Stack Using C Programming

#include<stdio.h>
#include<conio.h>
#define col 4
#define row 4

void main()
{
            int i,n,j;
            float ax[row+1], ay[col+1],diff[row+1][col+1],x,p,ya1,ya2,ya3,ya4,ya,ha;

            clrscr();

            printf("Enter thae value of n:");
            scanf("%d",&n);

            printf("\n Enter thae values of X and Y:\n");
            for(i=0; i<=n; i++)
            {
                        scanf("%f %f",&ax[i],&ay[i]);
            }

            printf("Value of X:");
            scanf("%f",&x);

            ha=ax[1]-ax[0];

            for(i=0; i<=n-1; i++)
                        diff[i][1]=ay[i+1]-ay[i];
            for(j=2; j<=row; j++)
                        for(i=0; i<=n-j; i++)
                                    diff[i][j]=diff[i+1][j-1]-diff[i][j-1];

            p=(x-ax[0])/ha;
            ya1=p*diff[0][1];
            ya2=p*(p-1)*diff[0][2]/2;
            ya3=p*(p-1)*(p-2)*diff[0][3]/6;
            ya4=p*(p-1)*(p-2)*(p-3)*diff[0][4]/24;
            ya=ay[0]+ya1+ya2+ya3+ya4;
            printf("%f",ya);
            getcha();



}

Friday, 2 May 2014

Quiz Game in C

#include<stdio.h>
#include<conio.h>
#include<dos.h>
void valid()
{
printf("\n \n Correct Answer\n");
}
void invalid()
{
printf("\n \n Wrong Answer\n");
}
void wel()
{
printf("\n\n \t\t\tWelcome to the C quiz \n");
}
void note()
{
printf("\n\n\nBASIC RULES OF GAME:-");
printf("\n\n\n\t --> The quiz has 5 very basic questions of the C Programming Language.\n");
printf("\t --> Programe can accept only  digits not a character.\n");
printf("\t --> You get '+3' point for every correct answer and '-1' for every\n \t     incorrect answer.\n");
printf("\t --> you have to choose only one option from '1,2,3,4'. \n");
printf("\n\n\n\n\n");
}
void main()
{

int score=0;
int answer;
char array[10];
int x=400, y =400;
clrscr();
wel();
printf("\n\n \t\t\tEnter your name: ");
gets(array);
note();
printf("\t \t Q1) Why is it called 'C'& not 'D' ?\n");
printf("\n\n \t \t[1]C stands for code\n\n \t \t[2]The inventors name started with a C\n\n \t \t[3]It developed after a language called 'B'\n\n \t \t[4]Why should I care?\n");
scanf("%d", &answer);
if(answer==1||answer==2||answer==3||answer==4)
 {
  if(answer==3)
  {
  valid();
  score=score+3;
  }
 else
 {
 invalid();
 score=score-1;
 }
}
else
 {
 printf( "invalid\n" );
 }
delay(2000);
clrscr();
wel();
note();
printf("\n\n \t \tQ2) It was developed at?\n");
printf("\n \t \t [1]IBMt\n\n \t \t [2]Bell Labsn\n\n \t \t [3]MITt\n\n \t \t [4]Microsoft(?)\n");
scanf("%d", &answer);
if(answer==1||answer==2||answer==3||answer==4)
{
if(answer==2)
{
valid();
score=score+3;
}
else
{
invalid();
score=score-1;
}
}
else
{
printf( "invalid\n" );
}
delay(2000);
clrscr();
wel();
note();

printf("\n\n \t \tQ3) Which of these is not a C keyword as per ANSI C ?\n");
printf("\n \t \t [1]externt\n\n \t \t [2]volatilen\n\n \t \t [3]entert\n\n \t \t [4]break\n");
scanf("%d", &answer);
if(answer==1||answer==2||answer==3||answer==4)
{
if(answer==3)
{
valid();
score=score+3;
}
else
{
invalid();
score=score-1;
}
}
else
{
printf( "invalid\n" );
}
delay(2000);
clrscr();
wel();
note();

printf("\n\n \t \tQ4) What is ANSI, btw? ?\n");
printf("\n \t \t [1]Area of Natural and Scientific Interest\n\n \t \t [2]American National Standards Institute\n\n \t \t [3]American National Standardization Institute\n\n \t \t [4]American National Society Of Intellectuals\n");
scanf("%d", &answer);
if(answer==1||answer==2||answer==3||answer==4)
{
if(answer==2)
{
valid();
score=score+3;
}
else
{
invalid();
score=score-1;
}}
else
{
printf( "invalid\n" );
}
delay(2000);
clrscr();
wel();
note();

printf("\n\n \t \tQ5)Which of these concepts is NOT supported by C ?\n");
printf("\n \t \t [1]Pointers\n\n \t \t [2]Functions\n\n \t \t [3]Strings\n\n \t \t [4]Namespaces\n");
scanf("%d", &answer);
if(answer==1||answer==2||answer==3||answer==4)
{
if(answer==4)
{
valid();
score=score+3;
}
else
{
invalid();
score=score-1;
}
}
else
{
printf( "invalid\n" );
}
delay(2000);
clrscr();
wel();

textcolor ( 1 );
cprintf("\n\n\n\n\n\n\n\n              Thank You for taking the Quiz.");
puts(array);
printf("\n\n\n\n\t \t \tTotal Score is:- %d out of 15", score);
getch();
}

Sunday, 20 April 2014

Print Syntax In Color Using C Language

#include<conio.h>
#include<stdio.h>
void yellow()
{
    textcolor ( YELLOW );
    cprintf ("YELLOW Color Testing \n");
}
void main ()
{
printf("This is BLUE COLOR");
blue();

CPRINTF Uing C

#include<conio.h>
#include<stdio.h>
void yellow()
{
    textcolor ( YELLOW );
    cprintf ("YELLOW Color Testing \n");
}
void blue()
{
    textcolor ( BLUE);
    cprintf ("Blue Color Testing \n");
}
void main ()
{
printf("This is YELLOW COLOR");
yellow();
printf("This is BLUE COLOR");
blue();